A majority element is an element that makes up more than half of the items in an array. Given a positive integers array, find the majority element. If there is no majority element, return -1. Do this in O(N) time and O(1) space.
Example 1:
Input: [1,2,5,9,5,9,5,5,5] Output: 5
Example 2:
Input: [3,2] Output: -1
Example 3:
Input: [2,2,1,1,1,2,2] Output: 2
Boyer–Moore majority vote algorithm
class Solution:
def majorityElement(self, nums: List[int]) -> int:
cnt = major = 0
for num in nums:
if cnt == 0:
major = num
cnt = 1
else:
cnt += (1 if major == num else -1)
return majorclass Solution {
public int majorityElement(int[] nums) {
int cnt = 0, major = 0;
for (int num : nums) {
if (cnt == 0) {
major = num;
cnt = 1;
} else {
cnt += (major == num ? 1 : -1);
}
}
return major;
}
}/**
* @param {number[]} nums
* @return {number}
*/
var majorityElement = function(nums) {
let cnt = 0;
let major = 0;
for (const num of nums) {
if (cnt == 0) {
major = num;
cnt = 1;
} else {
cnt += (major == num ? 1 : -1);
}
}
return major;
};class Solution {
public:
int majorityElement(vector<int>& nums) {
int cnt = 0, major = 0;
for (int num : nums) {
if (cnt == 0) {
major = num;
cnt = 1;
} else {
cnt += (major == num ? 1 : -1);
}
}
return major;
}
};public class Solution {
public int MajorityElement(int[] nums) {
int cnt = 0, major = 0;
foreach (int num in nums)
{
if (cnt == 0)
{
major = num;
cnt = 1;
}
else
{
cnt += (major == num ? 1 : -1);
}
}
return major;
}
}